Question
Find the limit. Use l'Hospital's Rule where appropriate. If there is a more elementary method, consider using it. If l'Hospital's Rule doesn't apply, explain why.$ \displaystyle \lim_{x\to 1/2} \frac{6x^2 + 5x - 4}{4x^2 + 16x - 9} $
Step 1
The numerator factors to $(3x+4)(2x-1)$ and the denominator factors to $(2x+9)(2x-1)$. So, the expression becomes: \[ \frac{(3x+4)(2x-1)}{(2x+9)(2x-1)} \] Show more…
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