Question
Find the magnetic force exerted on a proton moving east at a speed of $6.0 \times 10^{6} \mathrm{m} / \mathrm{s}$ by a horizontal magnetic field of $2.50 \mathrm{T}$ directed north.
Step 1
The proton is moving east at a speed of $6.0 \times 10^{6} \mathrm{m} / \mathrm{s}$ and the magnetic field is directed north with a magnitude of $2.50 \mathrm{T}$. The charge of a proton is $1.6 \times 10^{-19} \mathrm{C}$. Show more…
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Find the magnetic force exerted on a proton moving east at a speed of $6.0 \times 10^{6} \mathrm{m} / \mathrm{s}$ by a horizontal magnetic ficld of $2.50 \mathrm{T}$ directed north.
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The magnetic field of Earth at a certain location is directed vertically downward and has a magnitude of $50.0 \mu \mathrm{T}$. A proton is moving horizontally toward the west in this field with a speed of $6.20 \times 10^{6} \mathrm{~m} / \mathrm{s}$. What are the direction and magnitude of the magnetic force the field exerts on the proton?
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