Question
Find the magnitude and direction angle for each vector. See Example 1.$$\langle 8 \sqrt{2},-8 \sqrt{2}\rangle$$
Step 1
The magnitude of a vector $\langle a, b \rangle$ is given by $\sqrt{a^2 + b^2}$. Here, $a = 8\sqrt{2}$ and $b = -8\sqrt{2}$. So, the magnitude is $\sqrt{(8\sqrt{2})^2 + (-8\sqrt{2})^2} = \sqrt{256} = 16$. Show more…
Show all steps
Your feedback will help us improve your experience
Sarah Parrigin and 79 other Precalculus educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Find the magnitude and direction angle for each vector. $$\langle 8 \sqrt{2},-8 \sqrt{2}\rangle$$
Applications of Trigonometry
Vectors, Operations, and the Dot Product
Find the magnitude and direction angle for $\mathbf{u}$. See Example 1 . $$\langle 8 \sqrt{2},-8 \sqrt{2}\rangle$$
Find the magnitude and direction angle for each vector. See Example 1. $$\langle 8 \sqrt{2},-8 \sqrt{2}\rangle$$
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD