The magnitude of a vector $\mathbf{u} = \langle a, b \rangle$ is given by the formula $\sqrt{a^2 + b^2}$. In this case, $a = 8\sqrt{2}$ and $b = -8\sqrt{2}$.
So, the magnitude of $\mathbf{u}$ is $\sqrt{(8\sqrt{2})^2 + (-8\sqrt{2})^2} = \sqrt{128 + 128} =
Show more…