00:01
Here in this problem we have to find mean variance and standard deviation using shortcut method.
00:07
So here we have given the following information.
00:11
Now we will find the mid values of this class interval, that is xi.
00:17
So we get 72 .5, 77 .5, 82 .5, 87 .5, 87 .5, 87 .5, 97 .5, 92 .5, 97 .5, 97 .5 .9.
00:41
102 .5, 107 .5 and 112 .5.
00:54
Let assumed mean is equals to 92 .5.
01:09
Now in order to find the mean, first of all, we will find ui, which is equals to xi minus assumed mean, that is 92 .5 upon 5.
01:26
So it would be minus 4.
01:32
Minus 3 minus 2 minus 1 0 1 2 1 2 and 4 now we will find fi ui it would be 3 into minus 4 is minus 12 4 into minus 3 is minus 12 7 into minus 2 is minus 14 7 into minus 1 is minus 7 15 7 into minus 1 is minus 7 15 into 0 is 0 9 into 1 is 9 6 into 2 is 12 6 into 3 is 18 and 3 into 4 is 12 and the summation of fiui is 6 similarly we will find fiui square it would be 48 36 28 7 0 9 24 and 48 and the summation of fiui square is 254.
02:59
Now we know that mean is equals to a plus sigma fiui upon n into h...