The volume of a sphere is given by the formula $V = \frac{4}{3}\pi r^3$, where $r$ is the radius of the sphere. In this case, the radius of the nucleus is on the order of $10^{-15} \mathrm{m}$, so we can approximate it as $r = 10^{-15} \mathrm{m}$. Plugging this
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