00:01
Okay, so here we have one over x squared times the quantity, x squared minus two, which we notice is a proper fraction here because we have the numerator has a lower degree than the denominator.
00:12
And, well, we're already kind of factored, but we can factor this further, right? x squared minus two factors as x plus root two times x minus root two.
00:21
So then we have, well, we have our first constant a over, we have an x squared.
00:26
We have to account for the square.
00:28
So we have a over x and then plus b over x squared and then plus c over our next factor, which would be x plus root 2, plus d over our next factors be x minus root 2.
00:40
Okay.
00:41
So now to go ahead and clear the denominator, we have to multiply both sides of our equation by x squared times x plus root 2 times x minus root 2.
00:55
So that gives us 1 is equal to a x times x squared minus 2 plus b times x squared minus 2 plus c times x squared 2 plus d times x squared times the quantity x plus root 2.
01:13
Okay, but if we just substitute in 0 for x, then we see that 1 is just equal to b times negative 2.
01:21
Okay, well, just to find negative 2 here, and we see that b, right, this implies that b is equal to, well, negative 1⁄2.
01:31
So that b is equal to negative 1⁄2.
01:34
Okay.
01:37
And then if we substitute in square root of 2 for x, we have that 1 is equal to c times 2 times negative 2 times the square root of 4...