Find the points on the curve $ y = 2x^3 + 3x^2 - 12x + 1 $ where the tangent is horizontal.
(-2,21) and (1,-6)
Hey, it's Claire is the one you married here, So we're first gonna differentiate her function. We got six x square plus six X minus 12. We're gonna study equal to zero to find where the points where the tension line is horizontal. You get six x plus two times X minus one. So we see that X bias are negative, too. And one, we plug this in to our original equation to negative two comma 21 and one common negative six.