00:01
In this exercise, we're going to be finding the rejection region for each of the hypothesis tests given below, and we're going to assume that the population is normally distributed.
00:18
In the first case, we are testing the null hypothesis that the population mean is equal to 27 versus the alternative hypothesis that the population mean is less than 27.
00:30
And the level of significance is 0 .05 and the sample size is 12 and the population standard deviation is 2 .2.
00:44
Now for this, since the population standard deviation is known, we're going to use the z statistic test statistic.
00:55
Now in this case, for us to determine the rejection region, we have to do.
01:03
Think about a left tail test here and since the left tail is a negative the critical value is going to be negative we check from the table and the value that corresponds to the 0 .05 levels of significance is that z is less than or equal to negative 1 .645.
01:37
For the second case, their alternative hypothesis is that the population mean is not equal to 52.
01:47
So that makes this a two -tailed test.
01:52
And in this case, we shall have to get two critical values, the positive and the negative critical value.
02:01
And since the population standard deviation is unknown, we shall use the t table so what we're looking for is plus or minus t for a two -tail test with a degrees of freedom as n minus one so in this case it's plus or minus t as 0 .0 25 and the degrees of freedom would be equal to five because that's six minus one so on the table you'll find that this corresponds to plus or minus 2 .571.
02:45
So that tells us that the value of t should be lessen or equal to negative 2 .571 or it should be greater than or equal to positive 2 .571.
03:00
Next, we are comparing, we are testing the hypothesis that the mean is equal to negative negative 105 versus the mean is greater than negative 105...