Question
Find the resistance of $85.5 \mathrm{m}$ of No. 20 aluminum wire $\left(\rho=2.83 \times 10^{-6} \Omega \mathrm{cm},\right.$ $\left.A=2.07 \times 10^{-2} \mathrm{cm}^{2}\right)$
Step 1
We know that 1 meter is equal to 100 centimeters. So, we multiply the length of the wire in meters by 100 to get the length in centimeters. \[ L = 85.5 \, m \times 100 \, cm/m = 8550 \, cm \] Show more…
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