Question
Find the shortest distance between the curves$9 x^{2}+9 y^{2}-30 y+16=0$ and $y^{2}=x^{3} .$
Step 1
We can do this by dividing the entire equation by 9 and completing the square for the y terms. This gives us: \[x^{2}+(y-\frac{5}{3})^{2}=\frac{49}{9}\] This represents a circle with center at $(0, \frac{5}{3})$ and radius $\frac{7}{3}$. Show more…
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