Question
Find the shortest distance between the curves$y^{2}=4 x$ and $x^{2}+y^{2}-12 x+31=0 .$
Step 1
The given curves are $y^{2}=4x$ and $x^{2}+y^{2}-12x+31=0$. For the parabola $y^{2}=4x$, the slope of the tangent at any point is given by $\frac{dy}{dx} = \frac{4}{2y}$. Show more…
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