Question
Finding an Indefinite Integral In Exercises $15-46$ , find the indefinite integral. $$\int \frac{x+1}{\sqrt{3 x^{2}+6 x}} d x$$
Step 1
To find the indefinite integral of $\frac{x+1}{\sqrt{3x^2+6x}}$, we can start by factoring out a common factor of $x$ from the numerator: $$\int \frac{x+1}{\sqrt{3x^2+6x}} dx = \int \frac{x(1+\frac{1}{x})}{\sqrt{3x(x+2)}} dx$$ Show more…
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