00:01
For this exercise, we have to calculate the classical time lag of the photoelectric effect, given that the intensity of the radiation is 0 .01 watts per meter squared, and the area of the atom is 0 .1 nanometers, all of this squared, which is the same as 10 to the minus 20 meters squared.
00:25
So for the first part of the exercise, question a, we have to calculate how much energy per second does the atom absorb? well, the energy per second is going to be the power absorbed, and that's going to be the intensity of the light, the intensity of the radiation times the area of the atom, and that is 0 .01 in watts per meter squared times 10 to the minus 20th, which is 10 to the minus 22.
00:57
This is in watts or joules per second.
01:00
So this is the energy.
01:02
Per second that will be absorbed by our atom.
01:10
In question b, we are given the work function of the material two electron volts, and we have to calculate how much time does it take for the radiation to be able to remove an electron from this material? well, the work function is the energy required to remove an electron from the material.
01:36
So the time it's going to take for this radiation to give the atom this much energy is going to be phi the energy required over the power, which is the energy per unit time that the atom absorbs...