00:03
Okay, so for a, let's see if this graph of f of x is 1 to 1.
00:09
Okay, so normally if you have y equals 5 x minus 2, okay, it is not one to one.
00:22
But notice here, okay, so now we restrict the range of the domain of x.
00:28
Okay, so x can only be greater or equals 0.
00:34
So the graph is only kept the right half, okay? so now f x is 1 to 1 since x is greater equals 0.
00:53
So for b, let's find inverse of f of x.
00:58
So let's switch the position of x and 1.
01:01
So x equals 5 y squared minus 2.
01:06
So x plus 2 equals 5 times y squared...