00:01
Okay, the key idea for this question is, if you're ever asked if two transformations commute, that is t1 composed with t2 is t2 composed with t1, to check that, all you have to do is check if the matrices, the standard matrices for the transformations commute.
00:21
So a times b is equal to b times a.
00:24
So again, transformations commute if and only if their standard matrices commute.
00:29
So if we're asking if t1 and t2 commute where t1 is the reflection about the x axes, sorry, a reflection about y equals x, and t2 is projection onto the x axes, the first thing we need to do is noor matrices for these reflections.
00:48
So t1 reflecting about the line y equals x, that has the standard matrix 0110, and then t2 projecting onto the x -axis has the standard matrix 1 -0 -0.
01:07
So now, again, this is a and this is b.
01:14
So now all we have to do is perform a matrix multiplication.
01:19
A -b is going to look like 0 -110 times by 1 -0 -0 -0.
01:30
And if we do that calculation, we're going to get 0 times 1 plus 1 times 0, which is 0.
01:40
Second column in the first row is going to be 0, 0 times 0 plus 1 times 0.
01:48
Down here in the bottom left, we're going to have 1 times 1 plus 0 times 0, which is 1.
01:56
And then the final entry we have 1 times 0 plus 0 times 0 which is 0.
02:04
So that's what a -b is.
02:07
And then we also need to calculate b times a in the reverse order.
02:14
And so we have 1 -0 -0 -0.
02:18
That's b times a, 0 -1 -1 -0.
02:23
And remember with matrix multiplication, it's not a given that these two things are actually equal.
02:28
We have to actually do the computation.
02:31
Okay, so if i multiply the matrices in this order, 1 times 0 plus 0 times 1 plus 0 times 0 gets me 1.
02:43
0 times 0 plus 0 times 1 gets me 0.
02:50
And finally, 0 times 1 plus 0 times 0 gets me 0.
02:56
So now these two matrices are not equal.
03:05
So that tells us t1, excuse me, t1 composed with t2 is not equal to t2 composed with t1.
03:20
So those transformations do not commute.
03:25
All righty, let's check another problem here.
03:29
In this case, t1 is reflection about the x axes.
03:33
Let's see if we can remember what that matrix looks like.
03:36
So reflecting about the x axes.
03:39
We're going to make the y coordinate 0, so that matrix is going to look like 1 -0 -0 -negative 1.
03:49
And then reflecting about the line y -equals x, that's the one we saw earlier...