00:01
So today we're calculating delta h, delta s, and delta g at 25 degrees celsius for the following reactions.
00:09
I've already listed delta h and s values from the appendix for each of these compounds.
00:17
So let's begin with calculating delta h.
00:21
We know that to calculate delta h, we have to use the formula.
00:28
Delta h is equal to summation of n of delta h of the products minus summation.
00:34
In of delta h of the reactants.
00:40
So using this equation, let's just substitute the values, starting with a.
00:47
So our product here is no2.
00:50
We have two moles.
00:54
So two times delta h value of no2 is 33 .2 minus our reactant is n204.
01:04
There's only one molecule.
01:06
So n204 is 9 .16.
01:13
Delta h is in kilojoules, kilojoules per mole.
01:25
A mole from here and the one divided by the mole gets cancelled here.
01:33
Similarly, one mole in two kilojoules per mole, the mole and the mole get cancelled.
01:44
So here you get 57 .24 kilojoules.
01:51
So that is the delta h for the first reaction.
01:55
Let's continue for the second reaction.
02:05
Hcl minus 92 .3.
02:12
We have more than one product here, so we're just going to summish.
02:15
We're going to do summation, so plus an h3, delta h of an h3 is minus 45 .9.
02:26
Next is minus our reactant, which is nh4cl, and nh4cl delta h is minus 3.
02:36
14 .4 .4.
02:41
These are all one mole.
02:44
So with the mole and mole getting cancelled and we're just going to do kilojole here.
02:51
So here we get a value of 176 .2 kilojoules.
03:00
Similarly for c, we have two moles.
03:07
Iron, fe, delta h value is zero.
03:13
We have two products, so we're going to do plus.
03:18
Three moles of h -2 -0.
03:23
Delta h -2 -0 is minus 241 .8 kilojol per mole.
03:36
It says our reactor.
03:38
We have three moles of h -2, delta -h of h -2 is 0.
03:47
And here we have two reactants.
03:52
So we're going to do minus the whole thing.
04:00
We have minus the summation of the react, delta h of the reactants.
04:05
So we're going to do minus summation.
04:10
Our other reactant is f .e .203, which is just one more.
04:16
F .e .203 delta h is minus 824 .2 .2.
04:25
Kilo -mole.
04:27
So this gives us a value of 98 .8 kilojou.
04:37
And finally d.
04:41
You have two moles in h3, which is minus 45 .9 kilojou per mole.
05:01
Our reactants are n2, zero, and three h2, which is also zero.
05:15
So that gives us minus minus 91 .8 kilojou.
05:22
So these are the values of delta h for these reactions.
05:27
Let's move on to delta s.
05:39
To calculate delta s, we use a similar formula.
05:47
Delta s is equal to summation of n delta s of the products minus summation of n delta s of the reactors...