Question
For Exercises 11-38, use the square root property to solve each equation. Write complex number solutions in the form a $\pm$ bi.$$(x+3)^{2}+25=0$$
Step 1
We have $(x+3)^2 + 25 = 0$. We want to rewrite this equation in the form $(x-a)^2 = b$, where $a$ and $b$ are real numbers. To do this, we can subtract 25 from both sides of the equation: $$(x+3)^2 = -25$$ Show more…
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