The polar form of a complex number $z = a + bi$ is $r(\cos \theta + i \sin \theta)$, where $r = \sqrt{a^2 + b^2}$ and $\theta = \arctan \left(\frac{b}{a}\right)$.
For $z = -\frac{3 \sqrt{3}}{2}+\frac{3}{2} i$, we have $r = 3$ and $\theta = \frac{5\pi}{6}$, so
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