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For Exercises $41-52,$ use $z=-\frac{3 \sqrt{3}}{2}+\frac{3}{2} i$ and $w=3 \sqrt{2}-3 i \sqrt{2}$ to compute the quantity, Express your answers in polar form using the principal argument.$$w^{3}$$
Step 1
The polar form of a complex number $z = a + bi$ is $r(\cos \theta + i \sin \theta)$, where $r = \sqrt{a^2 + b^2}$ and $\theta = \arctan \left(\frac{b}{a}\right)$. Show more…
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For Exercises $41-52,$ use $z=-\frac{3 \sqrt{3}}{2}+\frac{3}{2} i$ and $w=3 \sqrt{2}-3 i \sqrt{2}$ to compute the quantity, Express your answers in polar form using the principal argument. $$ \frac{w^{2}}{z^{3}} $$
Applications of Trigonometry
Polar Form of Complex Numbers
For Exercises $41-52,$ use $z=-\frac{3 \sqrt{3}}{2}+\frac{3}{2} i$ and $w=3 \sqrt{2}-3 i \sqrt{2}$ to compute the quantity, Express your answers in polar form using the principal argument. $$ \frac{w}{z^{2}} $$
For Exercises $41-52,$ use $z=-\frac{3 \sqrt{3}}{2}+\frac{3}{2} i$ and $w=3 \sqrt{2}-3 i \sqrt{2}$ to compute the quantity, Express your answers in polar form using the principal argument. $$ z^{3} w^{2} $$
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