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For Exercises $41-52,$ use $z=-\frac{3 \sqrt{3}}{2}+\frac{3}{2} i$ and $w=3 \sqrt{2}-3 i \sqrt{2}$ to compute the quantity, Express your answers in polar form using the principal argument.$$\frac{z^{2}}{w}$$
Step 1
The polar form of a complex number is $r(\cos \theta + i \sin \theta)$, where $r$ is the magnitude of the complex number and $\theta$ is the argument of the complex number. The magnitude of $z$ is $\sqrt{(-\frac{3 \sqrt{3}}{2})^2 + (\frac{3}{2})^2} = 3$ and the Show more…
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For Exercises $41-52,$ use $z=-\frac{3 \sqrt{3}}{2}+\frac{3}{2} i$ and $w=3 \sqrt{2}-3 i \sqrt{2}$ to compute the quantity, Express your answers in polar form using the principal argument. $$ \frac{w}{z^{2}} $$
Applications of Trigonometry
Polar Form of Complex Numbers
For Exercises $41-52,$ use $z=-\frac{3 \sqrt{3}}{2}+\frac{3}{2} i$ and $w=3 \sqrt{2}-3 i \sqrt{2}$ to compute the quantity, Express your answers in polar form using the principal argument. $$ \frac{w^{2}}{z^{3}} $$
For Exercises $41-52,$ use $z=-\frac{3 \sqrt{3}}{2}+\frac{3}{2} i$ and $w=3 \sqrt{2}-3 i \sqrt{2}$ to compute the quantity, Express your answers in polar form using the principal argument. $$ z^{3} w^{2} $$
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