00:01
In this problem, we have to find the position of specific nodes of our atom.
00:07
Now, we're given an equation specifically a wave function, and we have to use this to find the position of the nodes.
00:14
And remember, a node is where we would see zero electron density.
00:19
So let's review the equation we're given.
00:21
So this is a hydrogen atom with the principal quantum number 3, l is zero, and m subl is zero.
00:28
Remember, these are all quantum numbers.
00:30
So si of 300 or 300 would be equivalent to 1 over 81 times the square root of 3 pi, times 1 over a0 raised to the 3 halves.
00:42
We multiply that by 27 minus 18 sigma plus 2 sigma squared times e raised to negative sigma over 3.
00:51
Now sigma is equivalent to r times a not, and a0 is our bore radius.
00:57
So a not would be equivalent to 5 .29.
01:00
Times 10 to the negative 11th meters.
01:03
That's simply a constant.
01:04
That's just the bore radius for a hydrogen atom.
01:09
So now what we can do is we can replace everywhere we see sigma with r over a0.
01:16
And then remember, we're finding the nodes where this is zero electron density.
01:20
So we can set our entire equation equal to zero.
01:24
So we'd have zero equivalent to 1 over 81 times a square root of 3 pi times 1 over a0 raised to the 3 halves times 27 minus 18 times r over a0 plus 2 times r over a0 squared times e raised to negative r over 3 times a0.
01:45
Remember we just simply plugged in r over a0 wherever we saw a sigma...