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For $t>0$, find the Thévenin equivalent network seen by the capacitor in Eigure P4.31. Use that result to determine the associated time constant. Assume: $R_S=8 \mathrm{k} \Omega, V_S=40 \mathrm{~V}, C=350 \mu \mathrm{~F}$, and $R=24 \mathrm{k} \Omega$. (FIGURE CAN'T COPY) Figure P4.31

   For $t>0$, find the Thévenin equivalent network seen by the capacitor in Eigure P4.31. Use that result to determine the associated time constant. Assume: $R_S=8 \mathrm{k} \Omega, V_S=40 \mathrm{~V}, C=350 \mu \mathrm{~F}$, and $R=24 \mathrm{k} \Omega$.
(FIGURE CAN'T COPY)
Figure P4.31
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Principles and Applications of Electrical Engineering
Principles and Applications of Electrical Engineering
Giorgio Rizzoni,… 7th Edition
Chapter 4, Problem 31 ↓
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For $t>0$, find the Thévenin equivalent network seen by the capacitor in Eigure P4.31. Use that result to determine the associated time constant. Assume: $R_S=8 \mathrm{k} \Omega, V_S=40 \mathrm{~V}, C=350 \mu \mathrm{~F}$, and $R=24 \mathrm{k} \Omega$. (FIGURE CAN'T COPY) Figure P4.31
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Consider the circuit shown with $R_{1}=25 \Omega, R_{2}=33 \Omega$ $C_{1}=12 \mu \mathrm{F}, C_{2}=23 \mu \mathrm{F}, C_{3}=46 \mu \mathrm{F}, \quad$ and $\quad V=6.0 \mathrm{V}$ (a) Draw an equivalent circuit with one resistor and one capacitor and label it with the values of the equivalent resistor and capacitor. (b) A long time after switch $S$ is closed, what are the charge on capacitor $C_{1}$ and the current in resistor $R_{1} ?$ (c) What is the time constant of the circuit? (d) At what time after switch $S$ is closed is the voltage across the combination of three capacitors $50 \%$ of its final value? (FIGURE CAN'T COPY)

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00:01 In this problem we have a circuit that looks somewhat like this, a switch here, we have a battery here, we have a capacitor here, here and here, and we have two resistors here.
00:23 And we are asked to draw one, an equivalent circuit with all the capacitors and resistors combined.
00:33 R1 is 25 oms, r2 is 33 oms, c1 is 46 microferrets c2 is 12 microferrets and c3 is 23 and c3 is 23 micro ferrets c2 and c3 our r parallel so we do 12 plus 23 we get 35 microferds and since c1 and c r series we do the reciprocal 1 over 35 plus 1 over 46 and we get the overall capacitance is 19 .9 microferds.
01:44 The resistors are in series.
01:52 So we just add them together, 25 plus 33 equals 58 oms.
02:02 So our overall down, diagram is going to look like this.
02:34 And our resistance is 58 oms.
02:40 This is a.
02:42 For the next part we have to find out what the charge is after a long time has passed.
02:48 We will use the formula charge equals the capacitance times a change in voltage...
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