00:01
So we'll start with problem a, where we're converting palmitio coenzyme a into the transversion of edenoilcoenzyme a.
00:08
So the difference between these molecules can be seen here, where you have a single bond between these carbons, and you have a double bond between these carbon groups here.
00:19
So when you write that out into a form of an isolated bond between these molecules, you'll see that we are removing one of the hydrogens across the.
00:33
The double bond.
00:35
How that works is one electron goes back to the hydrogen here and we're basically separating these apart so that these electrons can be donated to make this double bond here, whereas these hydrogens are separated from the solution.
00:57
So if you remember leo siskir, since we're moving electrons around, you'll see that less electrons is oxidation and greater electrons is reduction.
01:11
So in this case we're adding an electron back to the carbon group and removing those hydrogens.
01:18
So this is an oxidation reaction.
01:22
A better way to categorize oxidation and reduction reactions is in reduction reactions you're typically adding hydrogen ions into a bond such as if you hydrogenate a double bond back into a single bond by adding those hydrogens back.
01:43
And oxidations either remove hydrogens or add oxygens, such as with removal of hydrogens here in this case.
01:54
And oxidation reactions are typically carried out by dehydrogenases.
02:04
Moving on to problem b, here we have l -lucine and delusine.
02:10
The difference between these molecules is in the configuration of the ammonia.
02:15
Group across the carbon bond here.
02:20
Now you'll see that the chemical formula has not changed.
02:23
We simply moved groups around.
02:26
When you look at an ion with a 3d configuration, this would form a sort of tetrahedral pattern to it.
02:39
So here we have a hydrogen, here we have the carboxyl group, the c -o -o, here we have the rest of the chain of the amino acid, and here we have the pneumonia group.
02:57
What it means by the l and the d form is basically the direction you'd move in a circle between the heaviest and the lightest atoms in the bond.
03:10
If you've taken an organic chemistry lesson, you might know what this means.
03:16
Otherwise, a better way to simplify this is if you draw a plane of symmetry down the bond of interest and you flip the molecules position across the line almost as a two -sided mirror, you'll see that the ammonia group from here, from the first molecule of l -lucine, moves over to the delusine part, as well as the hydrogen moves over to the left side of the delucine.
03:43
So when you have a mirror -like image of a molecule, this is an example of an isomerization.
03:52
Again, the chemical formula is the same.
03:57
Just the confirmation and the position of the molecules have changed across it.
04:03
Isomerizations are carried out typically by isomerases.
04:10
Moving on to problem c, here we have glucose being converted into a fructose.
04:17
So if you look at the difference between these molecules, you'll notice that these carbon chains up on top are the difference between the two.
04:25
If you look at the rest of the molecule, nothing has changed.
04:30
However, if you look in these groups, again, the chemical formula between the two still has not changed only the position of items so again this is another isomerization this one specifically is carried out by glucose isomerase moving on to problem d here we have glycerol being converted into g3p or glucose 3 phosphate you'll see this reaction as part of the glycolysis process so here you'll see the difference between this group here and this group in g3p...