00:01
In this problem, we are given a graph of g of x and we want to find the following limits or explain why they do not exist.
00:08
Our first limit is the limit when x approaches to 1 of g of x.
00:17
For a limit to exist, a limit must exist, must be equal when we approach 1 on the left -hand side and the right -hand side.
00:35
So looking at our graph here, we see that on the left -hand side, the limit when x approaches to 1 is equal to 1.
00:42
But the limit of g of x when x approaches to 1 on the right -hand side is equal to 0.
00:51
Since these two limits do not agree, it means that the limit when x approaches to 1 does not exist.
01:18
Our right does not exist.
01:19
Our d and e for does not exist.
01:22
Our second limit is the limit when x approaches to 2 of g of x.
01:30
Again, let's verify what happens on both the left -hand side and on the right -hand side.
01:41
On the left -hand side, we see that when x approaches to 2, g of x approaches to 1.
01:47
And similarly, on the right -hand side, when x approaches to 2, g of x is equal to 1.
01:52
Since these two limits agree, it means that the limit exists and that limit is equal to 1.
02:22
Next, we have the limit when x approaches to 3 of g of x.
02:38
So as before, let's verify what happens when we approach 3 on both the left and right -hand side.
02:53
So on the left -hand side, the limit is equal to 0.
02:56
On the right -hand side, the limit is also equal to 0.
03:03
Which means that the limit when x approaches to 3 of g of x is equal to 0.
03:09
It exists.
03:10
Although our limit exists, let's note that g of 3 is equal to 1.
03:27
Which means that despite the fact that the limit exists, g of x is actually not continuous at this point.
03:31
We call this a removable discontinuity...