00:03
Okay, this question asks you to make a conjecture about the sign of the second derivative in exercise number one.
00:16
Exercise number one had x at t is t squared plus one, and y at t was t over two.
00:28
And we found that d, y, d, y, d, x was one half, that's d, y, d, d, t, divided by 2t, and that's dx, d, d, t.
00:45
So we got 1 over 4t.
00:47
To take the second derivative of y with respect to x, i can't take the derivative with respect to t of d, y, d, x.
00:56
I need the derivative with respect to x of d, y, d, x.
00:59
So i do d, d, d, dt of d, y, dx divided by d, d, dt of x.
01:14
D, d, d, d, t, i wrote it incorrectly in the bottom.
01:17
It's ddt of dx.
01:21
So i have the dt's kind of cancel, and i have the second derivative of y in the top...