For the reaction
$$\mathrm{C}_{2} \mathrm{H}_{2}(g)+4 \mathrm{~F}_{2}(g) \longrightarrow 2 \mathrm{CF}_{4}(g)+\mathrm{H}_{2}(g)
$$$\Delta S^{\circ}$ is equal to $-358 \mathrm{~J} / \mathrm{K}$. Use this value and data from Appendix 4 to calculate the value of $S^{\circ}$ for $\mathrm{CF}_{4}(g)$.