00:01
Alright, this problem starts out with telling you to graph this function.
00:05
So go into y sub 1 and make sure that when you type this in, i did it in alpha y equals, that you have 300 over 3 plus 17 e to the negative 0 .0625 x.
00:23
Now, when you go to graph this, it's not going to show on your viewing window.
00:28
So you're probably going to want to change your viewing window even before you hit go.
00:34
Make your x min 0, make your x max 100.
00:41
I counted by tens, just to keep it clean a little bit.
00:47
Y min 0, y max 100, and i kept that scale also at 10.
00:56
And you should get a pretty nice picture of this on your viewing screen.
01:01
It's a nice logistic growth model.
01:06
It kind of looks like that.
01:08
So you get the idea of what it's supposed to look like for part a.
01:14
Part b wants to know, let's get the wording here, estimate the percent of defoliation if 2 ,000 egg masses are counted.
01:26
Alright, so 2 ,000 egg masses, that just means x is 2.
01:34
So on your graph, you're going to want to hit second and then the button for trace.
01:43
And it brings up your calculate menu.
01:46
And you want to choose option number one value.
01:49
And then go ahead and type in a 2.
01:53
And it'll come up x equals 2 on your screen.
01:57
And voila, all of a sudden you'll get an answer of 16 .6644, which you'll have to convert to 16 .7%.
02:10
Then part c says, estimate the number of egg masses that exist if you observe that approximately two -thirds of a forest is defoliated.
02:21
So that means you're going to let a y value equal 66 .67%, right? because that's the kind of answer we're getting.
02:28
So you want to go into y sub 2 now and let that equal 66 .67.
02:36
When you do that, go ahead and graph it.
02:38
You'll get a nice solid straight line coming across in there somewhere.
02:42
And we're going to look for the intersection point.
02:45
To do that, on your calculator again, you want to hit that second trace again.
02:52
But this time, choose option number five for intersect.
03:00
Now it gives you choices.
03:01
It says first curve, second curve, guess, and all that stuff.
03:04
Because these are the only two things on there.
03:06
All you have to do is press enter three times.
03:14
Press enter three times.
03:15
That's a really ugly three i already said for you.
03:17
Press enter three times.
03:19
All right? and then you'll get an answer for an x value of 38 .846372.
03:33
And again, remember, those x values are in thousands.
03:38
So basically i want to multiply by a thousand, which is the same as moving my decimal point three places to the right.
03:46
So that's a grand total of 38 ,846 eggs, egg masses.
03:52
I think they are.
03:57
All right.
03:58
Now part d requires the most work.
04:01
It says use calculus to estimate the value of x for which y is increasing most rapidly.
04:07
So what that's going to mean is in here you're talking about how fast your slope is changing.
04:12
So changing, changing, changing.
04:15
Well, in here it's going to change the most.
04:18
And that's where that critical point is.
04:19
That's basically where your poi is.
04:22
All right? so we have to figure out what that poi is.
04:26
Well, in order to find out pois and where the concavity changes from concave up to concave down in this graph, i have to do the second derivative.
04:37
So let's get some space.
04:41
And we have to take our function and do the second derivative.
04:46
So i think the easiest way to do that would be to write that denominator, 3 plus 17 e to the negative 0 .0625 x and raise that denominator to the negative one power.
05:01
I think that's going to be the easiest way.
05:04
All right.
05:04
So here we go.
05:05
Uh -oh.
05:07
Lost my screen there.
05:08
The easiest way to – oh, i did it again – is y prime equals.
05:13
All right.
05:13
Bring your exponent down.
05:16
So that's going to be a negative 300.
05:18
Keep all of that.
05:21
That gets raised and subtract one from the exponent, so that becomes a negative 2.
05:30
Chain rule says you have to take the derivative of what's inside.
05:33
The derivative of 3, of course, is 0.
05:35
The derivative of 17 e to the negative 0 .0625 x.
05:43
Remember, the derivative of e to the x is e to the x, so e to the u du.
05:47
So i got to take the derivative of that exponent also, and that's a negative 0 .0625.
05:54
All right.
05:56
Since we have to do a second derivative, we will clean this up a little bit to make it a little bit nicer.
06:01
Let's see.
06:02
Everything but the negative 2 exponent can stay on the top.
06:07
So this will be a negative 300 up there, a 17 e to the negative 0 .0625 x, and the negative 0 .0625 x.
06:21
Oh, no...