00:01
In this question, we have a circuit of four capacitors.
00:06
It is connected in this way.
00:16
So we have c1, here is c2, and then c3, c4.
00:37
C3 and c4.
00:40
And the battery is here.
00:42
So we are given that c1 is 3 .5 nanofarid.
00:48
C2 is 2 .1 nanofarid c3 is 1 .3 nanofarid c4 is 4 .9 nanofarid.
01:02
Okay, we want to find the equivalent capacitance of this circuit.
01:10
So we know that, okay, capacitors in series, okay, we have the equivalent, the equivalent equivalent capacitance is 1 over c1 plus 1 over c2, okay, and then take the reciprocal...