00:02
So the first thing we're looking here for is the concentration of the cl minus and no3 minus.
00:15
And we do this by calculating the initial moles of reactants when we give them concentrations and volumes.
00:22
And then from the balanced reaction, we can calculate the moles of vacl2 that can react with agno3 using our strogeometric ratios.
00:33
And then finally we move on to the last step of this part of the podcast.
00:38
Which is determining the concentrations.
00:42
So we have cl minus.
00:43
So we have the moles of cl minus left.
00:46
That is 1 .5 times 10 to minus 2, divided by the volume, 0 .450 equals 0 .033.
00:59
Then we have n03 minus 5 .0 times 10 to the minus divided by 0 .450.
01:09
The exact same calculation as the one above, 0 .0 .111.
01:18
And then the next portion of the podcast, we will discuss how we can calculate the molarity of ba2 plus.
01:42
So from here to the solution that we have above, we add 50 mils of 0 .10 molar, sulfuric acid...