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All right.
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Hello.
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Today we're going to be dealing with these four half reactions and how they will react in the presence of a hydrogen electrode or a reference electrode.
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Now, hydrogen electrode is special because it has a zero potential.
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We use it as a reference compared to other electrodes.
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So for our first consideration, we want to know with which of these four reactions will hydrogen be the cathode? now, if this is the cathode, that means that it is getting reduced, which means that the other substances are being oxidized.
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So, if we consider our e not total is going to be, if hydrogen is getting reduced, it's e not hydrogen minus our e not metal.
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Right? and we need our e not total to be positive for the reaction to occur, which means that our e not total, are if this is zero, right? that means that our e not metal should be less than zero, right? that way the negative will be positive.
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And that applies to here, here, and here.
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Or in essence, the three chemicals, though, the three half reactions that'll act as an anode and make hydrogen act as a cathode are cr3 plus, sorry, technical difficulties.
01:28
Cr3 plus, fe2 plus, and mg2 plus.
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Perfect.
01:39
Now we want to look at which cell will produce the highest potential.
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So we have two considerations, either hydrogen as an anode or hydrogen as a cathode.
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Now, the anode will only happen with copper, and that will have a total potential of 0 .337.
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We know that because from our, because hydrogen is zero...