00:01
Welcome to this tutorial.
00:04
Part a is essentially asking what the acceleration of the capsule is in relationship to the gravitational acceleration or gravity.
00:18
So if we start with part a, you must first select the correct equation based on newton's second law of motion and kinematic.
00:40
Formulation.
00:48
This particular equation, we can find that information out by solving for a.
00:58
So first, we must convert the 30011 kilometers per hour velocity component into meters per second.
01:22
The distance the capsule moves into the earth after impact is 81 centimeters or 0 .81 meters.
01:37
It started from some original velocity of zero.
01:42
So we cancel that out.
01:49
So now we can solve for a.
02:03
And we square 86 .4 meters per second.
02:08
We get 74, 65 meters squared, second squared.
02:15
Then two times the depth of impression.
02:21
0 .81 meters is 1 .62 meters.
02:29
That leaves us with, a collision acceleration of 4 ,608 meters per second squared, then divided into gravitational acceleration.
02:49
We have approximately 470 times gravitational acceleration are 470 gs, which equates to 4 ,608 meters per second squared, collision acceleration.
03:17
So part a is asking what is the acceleration in meters per second squared and in gs during the crash? and the answer to part a is 470 gs or 4 ,608 meters per second squared.
03:49
To solve part b, we must calculate the multiples of force the crash exerted on the capsule by finding the summation of newton's second law of motion, force is equal to mass times acceleration...