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Suppose you want to name different carboxylic acids using appropriate iupac rules.
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Let's take this first example.
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Now, an important rule to note for iupac naming of carboxylic acids is that, well, carboxylic acids are always given highest priority.
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And what is meant by this is that no matter how many different functional groups are present in the molecule, if there is a carboxylic acid functional group, that will be given highest priority.
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And whichever carbon is attached to that functional group will have carbon number one.
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And that will be given our highest priority.
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So for this example, our carbon number one would be right here, which is right next to the oxygens of the carboxylic acid.
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In other words, it is the carboxylic acid carbon.
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And this is true for all molecules of carboxylic acids.
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So if we were to just follow along with nomenclature, as we've learned in the past, that you want to find the highest chain, or the longest chain.
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And if we were to number our carbons, we get two different paths.
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We get this red path and this blue path.
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Now, which one has more carbons? it would be the red path.
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So that will be our longest chain, and that will be our main chain for our molecule.
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So we know that four carbons is butane.
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Now, another rule for nomenclature is when there's a carboxylic acid, we will drop the e and add oic acid.
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So this is butan -oic acid.
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However, we are still not done, because we are.
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We still have this carbon right here that we need to take into account.
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And, well, that is one carbon, and we know that to be a methyl group, and it's attached to carbon two.
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So we will add methyl -2, two methylbutanoeic acid, and that is the name of our molecule.
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Let's try another example.
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Now, when there are alkenes present, carboxylic acids are still going to be given highest priority.
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They are given the highest priority out of any functional group.
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So we know that this chain will end with oic acid, or our name will end with oic acid.
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But how many carbons are in our chain? well, let's start by numbering them.
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Carbon number one would be right here with the carboxylic acid.
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Two, three, four, and five.
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So we've got pentane, so pentanoic acid.
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But we need to make sure to include that alken.
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So instead of pentenoic acid, we get rid of that a -n and add e -n in reference to our al -keen group.
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So it will be a pentinoic acid.
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However, with alkenes, we also need to take into account stereochemistry.
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So what stereochemistry would be present for an alkein, where the highest, priority relative to the alken are on the same side.
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Well, there are two ways to name that, and the first way is cis pentinoic acid, and the other way is z -pentinoic acid.
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But are we done? and the answer is, well, no, we are not done.
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And we need to take into account where our alken is.
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And it is on carbon number three, because we always take the lowest number for our alkenes or alkynes.
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So we will say either cis three pentinoic acid, or we will say z, should be in parentheses, three pentinoic acid.
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Because our highest priority groups relative to the alkenes are on the same side of the alken or the double bond.
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So we will use cis or z.
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Let's try this example.
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Now, this one is a little bit more challenging relative to the other molecules because although it looks like it has a carboxylic acid, it's a salt.
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It's not exactly a carboxylic acid.
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It is an ionic compound made with sodium and oxygen.
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So the oxygen would have a negative charge and the sodium would have a positive charge, making it an ionic compound.
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And how we name ionic compounds is say, so we have our alkan.
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And we know that with carboxylic acids, it would be called an alkenoic acid.
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Right? we just get rid of the e and we replace it with oic.
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And when we have salts, well, we replace our ick with 8.
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So it would be al -can -o -8 acid.
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And this is also true for esters because this is an ester molecule.
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And later when we will name esters, we will use 08 as our suffix as well.
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So that is a good note to keep in mind.
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And our first carbon will always be the carbon of our carboxylic acid...