Give IUPAC names for the following compounds: (a) The three isomers of C5 H12 b. c. d.

Name: Problem 11, Chapter 3: Organic chemistry with biological applications
Uploaded: 2022-03-05T10:42:49-08:00
Duration: 5 min 55 s
Channel: Anupa Sharad Medhekar
Description: Give IUPAC names for the following compounds: (a) The three isomers of C5 H12 b. c. d.

Give IUPAC names for the following compounds: (a) The three...

Key Concepts

IUPAC Nomenclature

IUPAC nomenclature is the systematic method of naming chemical compounds as recommended by the International Union of Pure and Applied Chemistry. It establishes rules for naming molecules by identifying the longest carbon chain, functional groups, substituents, and their positions, ensuring a unique and standardized name for each distinct structure.

Alkane Structure

Alkanes are saturated hydrocarbons consisting entirely of single bonds connecting carbon atoms, with a general formula CnH2n+2. Understanding the structure of alkanes is essential for systematic naming, especially when determining the parent chain and the locations of substituents.

Constitutional Isomerism

Constitutional isomers are compounds that share the same molecular formula but have different connectivity of atoms. In naming alkanes like C5H12, recognizing structural variations (such as differences in branching) is key to assigning correct IUPAC names for each unique isomer.

Substituent Naming and Positioning

Substituent naming involves identifying and naming the alkyl groups attached to the main carbon chain. Correctly numbering the positions (locants) of these substituents along the parent chain is critical to accurately describing the molecule's structure in its IUPAC name.

Transcript

00:03 In problem # 11.

00:06 We have to give names to given compounds component is maintained c five h 12 and three i summer so we have to write first i summer is when all carbon attempts are in one line.

00:23 So it is simply painting five carbon atoms and no double bond saturated hydrocarbon.

00:35 And we in so name is printing in the second i summer of plantain.

00:43 Four carbon attempts are in one line and one carbon is in the form of side chain with.

00:49 So we have to start select the longest carbon chain first this is the longest one and numbering it in such a way so that the carbon which is containing any side general functional group should get the least number.

01:06 So we are starting numbering from here 12, three and fourth and by this we can say at the second carbon atom, mythical group is present so it is do me tile to me tail beauty four carbon atoms in the longest chain.

01:35 So parent compound is beauty and after that 3rd 1 is three carbon attempts are in longest chain.

01:45 So it should be propane parent name and numbering is 12 and three second carbon to metal groups so that we have to mention in the name.

02:00 One it is 22 dimethyl style diameter hail probably and after that the b component which is given in the question is this one here again we have to follow the same rule that is first of all.

02:38 Select the longest chain for me so longest cheney's 12345.

02:46 That is painting is the parent name and number it in such a way so that the carbon which is containing any functional group.

02:54 Outside chain should get the least number.

02:57 So numbering should start from here.

02:59 It is one two three four and five.

03:07 So naming will be accordingly and we can say it is 23 23.

03:17 Damn it time 20.

03:34 And after that c compound again here we have to select the longest carbon chain.

03:40 1st longest is this one...