Question
Given a diode current of $6 \mathrm{~mA}, V_{T}=26 \mathrm{mV}, n=1$, and $I_{s}=1 \mathrm{nA}$, find the applied voltage $V_{D}$.
Step 1
Step 1: Recall the diode equation: $I_D = I_S (e^{\frac{V_D}{nV_T}} - 1)$ Show more…
Show all steps
Your feedback will help us improve your experience
Narayan Hari and 78 other educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A diode is operating with iD = 2 mA and vD = 0.82 V. (a) What is IS if n = 1? (b) What is the diode current for vD = -5 V?
We have a junction diode that has $i_{D}=$ $0.2 \mathrm{mA}$ for $v_{D}=0.6 \mathrm{V}$. Assume that $n=2$ and $V_{T}=0.026 \mathrm{V} .$ Use the Shockley equa. tion to compute the diode current at $v_{D}=$ $0.65 \mathrm{V}$ and at $v_{D}=0.70 \mathrm{V}.$
We have a junction diode that has iD = 0.2 mA for vD = 0.6 V. Assume that n = 2 and VT = 0.026 V. Use the Shockley equation to compute the diode current at vD = 0.65 V and at vD = 0.70 V.
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD