00:01
When you do the problem to have a limiting reactant, you don't know which one is the limiting reactant.
00:08
You have to use all of the mass of the reactant they give you, and you use it to calculate the mass of the product, which one gives the less amount of the product, that is the limiting reactant, and the amount of product is based on the amount of limiting reactant.
00:29
They're given to you.
00:30
So based on that idea, we do our problem 1111.
00:39
Let's see.
00:41
I have...
00:44
First of all, we have to balance the equation first.
00:49
We have a couple one oxide react with hydrogen.
00:54
The solid is a gas here.
00:58
And you will get a couple and water.
01:07
Okay.
01:10
And then they give you 30 points.
01:14
0 gram of copper oxide and how many grams, 12 grams of hydrogen.
01:21
And now you have, you want to know this one.
01:25
And first you have to calculate the mass of the couple, right? and now i start with the couple oxide first.
02:23
And when you calculate this one, they give you this equal, 206 .6 grams, 206 .6 grams.
02:35
Okay.
02:36
So when you use copper oxide, couple one outside, you call the mass of the couple, you have 26 .6 gram couple is reproduced, right? and now we use hydrogen.
02:58
Let's see how hydrogen give it to you.
03:04
So you have 12 .4.
04:01
So then we use how many grams? 7, 5, 7 .7 grams.
04:11
So our product is.
04:15
So, now go to b.
04:35
We do similar.
04:40
We have to balance an equation.
04:42
Before, we saw the problem all the time.
04:44
You have to balance first, and you do the problem.
04:50
If you don't do it, you get the raw answer.
04:55
So they give us 24 .3 grams.
04:59
And this, how many grams? also 10 grams.
05:11
A similar question, c...