Given the common base BJT bias circuit shown in Figure P11.55, let us calculate the location of the $Q$-point, assuming $\beta$ is large, if
$$
\begin{array}{ll}
R_1=6 \mathrm{k} \Omega & R_C=4.5 \mathrm{k} \Omega \\
R_2=1 \mathrm{k} \Omega & R_E=1.5 \mathrm{k} \Omega
\end{array}
$$
Note that this is exactly the same dc circuit as that previously discussed in the common emitter circuit configuration.
Figure P11.55 can't copy