00:01
Okay, for this problem, we're given two three -dimensional vectors.
00:05
The first one, vector a, is 3 i -hat minus 4 j -hat plus 4 k -hat, and vector b is equal to 2 -i -hat plus 3j -hat minus 7 k -hat.
00:28
And the first thing that we want to find is the vector c, where c is defined as a plus b, and we want it in component form as well as the magnitude.
00:42
Well, since we've got these lined up, we can just go ahead and add them.
00:47
3 plus 2 is equal to 5a5 i hat.
00:52
Minus 4 plus 3 is equal to minus 1 j hat.
00:55
You don't have to write the 1.
00:57
We can just say minus j hat.
00:59
And then 4 plus minus 7 is minus 3 k hat.
01:04
And so that is, in fact, the vector c.
01:08
The magnitude of c is going to be equal to each one of those components squared and then take the square root of it.
01:17
It's kind of like a super pythagoras theorem.
01:19
And so that's going to be 5 squared plus 1 squared plus 3 squared.
01:25
And then take the square root of that.
01:29
So that's 25 plus 10.
01:31
That's the square root of 35.
01:34
And so the magnitude of c is equal to 5 .9...