Question
Gold can be extracted from the surrounding rock by using a solution of sodium cyanide. While effective for isolating gold, toxic cyanide finds its way into watersheds, causing environmental damage and harming human health.$4 \mathrm{Au}(s)+8 \mathrm{NaCN}(a q)+\mathrm{O}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(\ell) \rightarrow$.$4 \mathrm{NaAu}(\mathrm{CN})_{2}(a q)+4 \mathrm{NaOH}(a q)$$2 \mathrm{NaAu}(\mathrm{CN})_{2}(a q)+\mathrm{Zn}(s) \rightarrow 2 \mathrm{Au}(s)+\mathrm{Na}_{2}\left[\mathrm{Zn}(\mathrm{CN})_{4}\right](a q)$.a. If a sample of rock contains $0.009 \%$ gold by mass, how much $\mathrm{NaCN}$ is needed to extract the gold from 1 metric ton ( 1 metric ton $=10^{3} \mathrm{kg}$ ) of rock as $\mathrm{NaAu}(\mathrm{CN})_{2} ?$b. How much zinc is needed to convert the $\mathrm{NaAu}(\mathrm{CN})_{2}$ from part (a) to metallic gold?c. The gold recovered in part (b) is manufactured into a gold ingot in the shape of a cube. The density of gold is $19.3 \mathrm{g} / \mathrm{cm}^{3} .$ How big is the cube of gold?
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Given that the rock contains 0.009% gold by mass, and we have 1 metric ton (or $10^{3}$ kg) of rock, the mass of gold in the rock is: \[0.009\% \times 10^{3} \, \text{kg} = 0.09 \, \text{kg} = 90 \, \text{g}\] Show more…
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Gold can be extracted from the surrounding rock by using a solution of sodium cyanide. While effective for isolating gold, toxic cyanide finds its way into watersheds, causing environmental damage and harming human health.$4 \mathrm{Au}(s)+8 \mathrm{NaCN}(a q)+\mathrm{O}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(\ell) \rightarrow$.$4 \mathrm{NaAu}(\mathrm{CN})_{2}(a q)+4 \mathrm{NaOH}(a q)$ $2 \mathrm{NaAu}(\mathrm{CN})_{2}(a q)+\mathrm{Zn}(s) \rightarrow 2 \mathrm{Au}(s)+\mathrm{Na}_{2}\left[\mathrm{Zn}(\mathrm{CN})_{4}\right](a q)$.a. If a sample of rock contains $0.009 \%$ gold by mass, how much $\mathrm{NaCN}$ is needed to extract the gold from 1 metric ton ( 1 metric ton $=10^{3} \mathrm{kg}$ ) of rock as $\mathrm{NaAu}(\mathrm{CN})_{2} ?$ b. How much zinc is needed to convert the $\mathrm{NaAu}(\mathrm{CN})_{2}$ from part (a) to metallic gold? c. The gold recovered in part (b) is manufactured into a gold ingot in the shape of a cube. The density of gold is $19.3 \mathrm{g} / \mathrm{cm}^{3} .$ How big is the cube of gold?
Mining for Gold Unlike most metals, gold is found in nature as the pure element. Miners in California in 1849 searched for gold nuggets and gold dust in stream beds, where the denser gold could be easily separated from sand and gravel. However, larger deposits of gold are found in veins of rock and can be separated chemically in a two-step process:$$\begin{aligned}&\text { (1) } 4 \mathrm{Au}(s)+8 \mathrm{NaCN}(a q)+\mathrm{O}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(\ell) \rightarrow\\&4 \mathrm{NaAu}(\mathrm{CN})_{2}(a q)+4 \mathrm{NaOH}(a q)\end{aligned}$$.$$\begin{aligned}&\text { (2) } 2 \mathrm{NaAu}(\mathrm{CN})_{2}(a q)+\mathrm{Zn}(s) \rightarrow\\&2 \mathrm{Au}(s)+\mathrm{Na}_{2}\left[\mathrm{Zn}(\mathrm{CN})_{4}\right](a q)\end{aligned}$$.If a $1.0 \times 10^{3} \mathrm{kg}$ sample of rock is $0.019 \%$ gold by mass, how much $\mathrm{Zn}$ is needed to react with the gold extracted from the rock? Assume that reactions (1) and (2) are $100 \%$ efficient.
Mining for Gold Unlike most metals, gold occurs in nature as the pure element. Miners in California in 1849 searched for gold nuggets and gold dust in streambeds, where the denser gold could be easily separated from sand and gravel. However, larger deposits of gold are found in veins of rock and can be separated chemically in the following two-step process: (1) $4 \mathrm{Au}(s)+8 \mathrm{NaCN}(a q)+\mathrm{O}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(\ell) \rightarrow$ $$4 \mathrm{NaAu}(\mathrm{CN})_{2}(a q)+4 \mathrm{NaOH}(a q)$$ (2) $2 \mathrm{NaAu}(\mathrm{CN})_{2}(a q)+\mathrm{Zn}(s) \rightarrow$ $$2 \mathrm{Au}(s)+\mathrm{Na}_{2}\left[\mathrm{Zn}(\mathrm{CN})_{4}\right](a q)$$ If 23 kilograms of ore is $0.19 \%$ gold by mass, how much Zn is needed to react with the gold in the ore? Assume that reactions 1 and 2 are $100 \%$ efficient.
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