For $f(x)=\sqrt{x}$:
When $x=0$, $f(0)=\sqrt{0}=0$, so the ordered pair is $(0,0)$.
When $x=1$, $f(1)=\sqrt{1}=1$, so the ordered pair is $(1,1)$.
When $x=4$, $f(4)=\sqrt{4}=2$, so the ordered pair is $(4,2)$.
When $x=9$, $f(9)=\sqrt{9}=3$, so the ordered pair is
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