00:01
Here we're going to be graphing a system of linear equations, estimating their solution, and then we're going to try and plug that solution back in algebraically and make sure it gives us the proper answer.
00:14
So let's start up by writing our two equations.
00:17
We have our 3x plus 6y equals 15, and then we have our negative 2x plus 3y equals negative 3.
00:27
So now let's solve these for our ys.
00:30
Because that makes it a lot easier to graph.
00:32
So we get 6y equals 15 minus 3x.
00:38
We divide by 6 to simplify.
00:40
We get y equals 15 over 6 minus 3 over 6, which is the same as 1 1ā2x.
00:49
And then we do the same thing to our other one.
00:53
So we'd get 3y equals 2x minus 3.
00:59
And we divide by 3 to simplify, we'd get y equals 2 thirds x minus 3 over 3, which is the same as 1.
01:09
So that's our other equation...