00:01
We are told that the angles for viewing red light minus the violet light is going to be 21 degrees.
00:18
So from violet to red is going to be the spectrum.
00:24
We're also told that m equals 1.
00:27
And so for a diffraction grading, lambda, equals d sine theta so lambda red is 700 nanometers and lambda violet is around 400 nanometers um so if we know that lambda r equals d sine theta r and we know that lambda v equals d sine theta v and we know this then i can substitute in for let's substitute for theta v so rearranging this theta v equals theta v equals theta r minus 21 degrees.
02:07
So d sine of theta r minus 21 degrees.
02:20
Okay.
02:31
So we know lambda r and lambda v.
02:37
We do not know theta r and we do not know theta v.
02:44
However, i can rearrange this.
02:46
And say that theta r is the inverse sign of lambda r over d.
03:03
So now i can substitute that into this last equation, lambda v equals d sine of theta r, but theta r is the inverse sign of lent.
03:24
Lambda r over d minus 21 degrees.
03:33
Okay, let's put that into a calculator, although i am actually solving for d, so it's actually going to be lambda v over the sign of the inverse sign of lambda r over d minus 21 degrees.
03:57
Okay.
04:01
Lambda v is 400 times 10 to the negative 9th power over the sign of the inverse sign of lambda r over d.
04:29
That should be lambda subr.
04:32
Lambda subr is 700 times 10, to the negative 9th power over d.
04:52
D? wait a minute.
04:55
That doesn't, i don't know what d is.
05:01
So let me think about what i did again here.
05:04
I substituted in.
05:08
And so, so i took theta r, no, theta v equals theta r minus 21.
05:30
I substituted that in.
05:31
So it would be d sign of theta r minus 21.
05:36
Okay.
05:42
And then lambda r.
05:57
Okay.
06:01
So what i'm thinking is that i have d twice in here...