Question

Halle el radio de curvatura de la trayectoria de un protón de $25,0 \mathrm{MeV}$ que se mueve perpendicularmente al campo de $1,20 \mathrm{~T}$ de un ciclotrón.

    Halle el radio de curvatura de la trayectoria de un protón de $25,0 \mathrm{MeV}$ que se mueve perpendicularmente al campo de $1,20 \mathrm{~T}$ de un ciclotrón.
Física Universitaria Volumen 2
Física Universitaria Volumen 2
William Moebs,… 1st Edition
Chapter 11, Problem 97 ↓

Instant Answer

verified

Step 1

0 \mathrm{MeV}$ and the magnetic field strength is $1.20 \mathrm{T}$.  Show more…

Show all steps

lock
AceChat toggle button
Close icon
Ace pointing down

Please give Ace some feedback

Your feedback will help us improve your experience

Thumb up icon Thumb down icon
Thanks for your feedback!
Profile picture
Halle el radio de curvatura de la trayectoria de un protón de $25,0 \mathrm{MeV}$ que se mueve perpendicularmente al campo de $1,20 \mathrm{~T}$ de un ciclotrón.
Close icon
Play audio
Feedback
Powered by NumerAI
*

Labs

-

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

*

Key Concepts

-
Lorentz Force
The Lorentz force is the force experienced by a charged particle moving in a magnetic field. It is given by the vector cross product of the particle's velocity and the magnetic field, resulting in a force perpendicular to both. This force causes the particle to undergo circular motion when its velocity is perpendicular to the magnetic field, and it is fundamental in understanding the dynamics of charged particles in electromagnetic environments.
Circular Motion in Magnetic Fields
When a charged particle moves perpendicularly through a uniform magnetic field, it experiences a constant magnitude force that acts as a centripetal force, causing it to follow a circular path. The radius of this path, or the radius of curvature, is determined by the balance between the magnetic force and the centripetal force, typically expressed as r = p/(qB), where p is the momentum of the particle, q its charge, and B the magnetic field strength.
Kinetic Energy and Momentum Relationship
In mechanics, the kinetic energy of a particle is related to its momentum. For non-relativistic speeds, the relationship can be expressed through the kinetic energy formula, which allows one to calculate the particle's velocity, and hence its momentum, from its kinetic energy. This relationship is essential when determining characteristics of motion, such as the radius of curvature, for particles moving in a magnetic field.

*

Recommended Videos

-
find-the-radius-of-curvature-in-m-of-the-path-of-0220-mev-proton-moving-perpendicularly-to-the-130-field-of-a-cyclotron-36381

Find the radius of curvature (in m) of the path of a 0.220 MeV proton moving perpendicularly to the 1.30 T field of a cyclotron.

find-the-radius-of-curvature-in-m-of-the-path-of-a-0260-mev-proton-moving-perpendicularly-to-the-115-t-field-of-a-cyclotron-88025

Find the radius of curvature (in m) of the path of a 0.260 MeV proton moving perpendicularly to the 1.15 T field of a cyclotron.

Need help? Use Ace
Ace is your personal tutor. It breaks down any question with clear steps so you can learn.
Start Using Ace
Ace is your personal tutor for learning
Step-by-step explanations
Instant summaries
Summarize YouTube videos
Understand textbook images or PDFs
Study tools like quizzes and flashcards
Listen to your notes as a podcast
Continue solving this problem
Create a free account to:
  • View full step-by-step solution
  • Ask follow-up questions with Ace AI
  • Save progress and study later
Continue Free
Join the community

18,000,000+

Students on Numerade


Trusted by students at 8,000+ universities

Numerade

Get step-by-step video solution
from top educators

Continue with Clever
or



By creating an account, you agree to the Terms of Service and Privacy Policy
Already have an account? Log In

A free answer
just for you

Watch the video solution with this free unlock.

Numerade

Log in to watch this video
...and 100,000,000 more!


EMAIL

PASSWORD

OR
Continue with Clever