00:01
The torque acting at point a will be equal to ta.
00:04
So this will be equals to force multiplied by oa.
00:09
So the force given is 125 lv fit per feet multiplied by the value of oa.
00:25
Oa is 2 11 inch or 1 feet.
00:29
So this will be equals to 125 lv fit.
00:36
Now let us calculate the polar moment of inner seat.
00:40
So we will write j, this will be equal to pi divided by 32, do to the power of 4 minus d ,i to the power of 4.
00:51
So it will be equal to pi divided by 32, do is given as 2 .5 to the power of 4 minus d .i is given as 2 .3 to the power of 4.
01:02
So it will come out to be 1 .076 inch to the power of 4.
01:11
Now let us determine the cr stage developed at point a.
01:16
So we will write tau -a.
01:18
This will be equals to pa multiplied by ro divided by the polar moment of inertia.
01:25
So let us put the values.
01:27
The ta value is 125 lb fit...