00:02
In this question, there are two heat engines, x and y.
00:05
So we are given this relationship.
00:09
So qh of x is 4 times of qh of y.
00:17
Okay.
00:20
And then you are also given that w engine of x is equal to 2 times the work done by engine of y and then we also know that qc of x is seven times the qc of y okay and then we always have this relationship qh is equal to w engine plus qc okay so that means that if look at x or heat engine x.
01:14
So in this question we need to find the efficiencies of heat engines x and y.
01:21
So for heat engine x we have qh x equals to w engine of x plus qc of x.
01:35
Okay.
01:37
So you can then try to find so in part a we need to find the efficiency of x, engine x, right? so one thing we know is that e of x is equal to w engine of x, devoured by qh of x.
02:00
Okay, so we need to try and see what we can do with, what we can find with w engine x and qh of x.
02:10
Okay, so, so if you substitute so you can proceed to do part a so we have qh of x equals to w engine of x plus qc of x so this is equal to 4 qh of y equals to 2 w engine of y plus 7 times of qc of y so notes that we also have qhy equals to w engine of y plus qc of y.
02:58
Okay, so this equality holds.
03:01
So if you look at this equation, we can actually obtain this.
03:08
2 qh of y equals to 5 qc of y.
03:13
So you just remove two engine of x and using this equation, okay, and then we can obtain this.
03:25
That means that qh of y is equal to 2 .5 qc of y.
03:38
Then the next thing is, so now we try to find wx, okay, in terms of qc, c, so we can find that given that qh of y is 2 .5 qc of y, right? so we can actually obtain so w and g not y.
04:26
It is going to be qh of y minus qc of y...