Question
How does the ratio of substitution product to elimination product formed from the reaction of propyl bromide with $\mathrm{CH}_{3} \mathrm{O}^{-}$ in methanol change if the nucleophile is changed to $\mathrm{CH}_{3} \mathrm{S}^{-}$ ?
Step 1
In a protic solvent, a more polarizable nucleophile is a better nucleophile. In this case, $CH_{3}S^{-}$ is more polarizable than $CH_{3}O^{-}$, making it a better nucleophile. Show more…
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