Question
How far apart are two conducting plates that have an electric field strength of $4.50 \times 10^{3} \mathrm{V} / \mathrm{m}$ between them, if their potential difference is 15.0 $\mathrm{kV}$ ?
Step 1
We know that 1 kilovolt equals 1000 volts. So, the potential difference $V$ is $15.0 \times 10^{3} \, \mathrm{V}$. Show more…
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