00:01
Okay, so we've got a buffer.
00:02
So let's start by finding out the moles of the two components of our buffer that we have.
00:07
We're starting with 10 .0 grams of ammonium chloride.
00:13
So let's go ahead and change that to moles.
00:16
We use the molar mass, which is 53 .5.
00:21
And we'll see we get 0 .187 moles of the ammonium ion.
00:31
And we know that we've been given that we have 0 .15 molar nh3, and since we have one liter of it, we've got 0 .150 moles of nh3.
00:52
Okay? and we know that our k -a for ammonium ion will be 5 .6 times 10 and negative 10.
01:08
So we'll go ahead and plug in our buffer equation where h plus.
01:13
Is k .a.
01:15
So 5 .6 times 10 and negative 10 times the moles of acid over the moles of base.
01:23
So 0 .187 moles of acid over 0 .150 moles of base.
01:34
And that'll give us a concentration of h plus, which is 6 .98 times 10 to negative 10.
01:43
And if i take minus the log of that, that will give me a ph.
01:47
Of 9 .16...