How many milligrams of calcium chloride dihydrate CaCl2 ·2 H2 O (molecular weight =147 g / mol

step 1 Hi, so in this question I need to find how many mill equivalent of calcium is given So given tha

How many milligrams of calcium chloride dihydrate CaCl2 ·2...

How many milligrams of calcium chloride dihydrate $\mathrm{CaCl}_2 \cdot 2 \mathrm{H}_2 \mathrm{O}$ (molecular weight $=147 \mathrm{~g} / \mathrm{mol}$ ), are needed to prepare $500 \mathrm{~mL}$ of solution containing $5 \mathrm{mEq} /$ liter $\mathrm{Ca}^{+2}$ ?

Key Concepts

Milliequivalents

Milliequivalents (mEq) are a unit used to express the chemical reactivity of ions in a solution, taking into account both the concentration in moles and the valence (charge) of the ion. It is particularly useful in situations where the ion’s charge influences its activity, such as in electrolyte solutions.

Molecular Weight

Molecular weight is the sum of the atomic weights of all the atoms in a molecule. It is essential in stoichiometric calculations as it allows conversion between the mass of a substance and the number of moles, which is critical for preparing solutions with precise concentrations.

Stoichiometry of Ionic Compounds

Stoichiometry in ionic compounds involves understanding the proportion in which ions are present, including the relationship between the salt and its constituent ions when it dissociates in solution. This is crucial when calculating how much of a compound is needed to achieve a specific ion concentration in a solution.

Solution Concentration and Volume Conversion

Preparing a solution with a specified concentration requires an accurate understanding of the relationship between solute quantity, solution volume, and concentration units. This includes converting between different volume and mass units, such as liters to milliliters and grams to milligrams, to ensure the correct amount of solute is used.

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