How much heat is required to raise an 800-g copper pan from 15^∘ C to 90^∘ C if (a) the pan is e

How much heat is required to raise an 800-g copper pan from...

How much heat is required to raise an $800-\mathrm{g}$ copper pan from $15^{\circ} \mathrm{C}$ to $90^{\circ} \mathrm{C}$ if (a) the pan is empty or contains
(b) $1.0 \mathrm{~kg}$ of water and (c) $4.0 \mathrm{~kg}$ of mercury?

Key Concepts

Specific Heat Capacity

This property defines how much energy is required to raise the temperature of a unit mass of a substance by one degree Celsius (or Kelvin). It varies between materials and is essential for determining the energy needed to heat or cool any given substance.

Heat Energy Calculation (Q = m·c·?T)

The equation Q = m·c·?T is fundamental in thermodynamics and calorimetry, where Q represents the heat energy transferred, m is the mass of the substance, c is its specific heat capacity, and ?T is the change in temperature. This formula is used to calculate the energy required to achieve a specified temperature change.

Temperature Change (?T)

This refers to the difference between the final and initial temperatures of a system. It is a critical factor in the computation of heat transfer, as the energy required is directly proportional to how much the temperature is altered.

Calorimetry

Calorimetry is the field of science that deals with measuring the amount of heat absorbed or released during physical and chemical changes. It encompasses the techniques and principles used to quantify heat transfer using methods such as the specific heat capacity formula.

Transcript

00:01 So question one was asking us, how much heat is required if the pan is empty? okay? so if the pan is empty, just pain yourself.

00:11 So we know the heat equation is q equal to mc delta t.

00:14 M is the mass.

00:15 C is the specific heat.

00:16 Delta t is the temperature change.

00:18 If we plug in, we'll get mass, is given as 0 .8 kilograms times the specific heat of the copper pan.

00:26 The specific for calvert is 386 jou per kilogram times carbon, okay? tans the changing temperature, which is 90 degrees celsius minus 15 degrees celsius.

00:44 And this will give us the amount of heat will be equal to 23 .16 kilojew.

00:59 Okay? and for question b, you want us to calculate the amount of of heats that will be required to raise an 800 grand copper pan from 15 degrees celsius to 90 degrees celsius if the pan is contained with 1 kilogram of water okay so in this case let's say q total is equal to the heat that required from an empty pan which is q plus q1 which is the heats that will be required to raise the temperature for the water okay i say q1 and this this will give us 23 .16 kilojou plus m1 is the mass of water times c1, the c1, the specific of the water, and then times the delta t, which is the changing temperature, is the same.

01:57 Okay? and this will give us 23 .16 kilojou plus m1 is 1 ,000, 1 .0 kilogram ,000, times 4 ,0001 .1 .1 ,000, times 4 ,000.

02:21 184, jew per kilogramme 10 kelvin times the changing temperature, which is 90 degrees celsius, minus 15 degrees celsius, which is 75 degrees celsius.

02:37 You see here is jew per kilogram and i have a temperature of degree celsius.

02:43 It doesn't matter.

02:44 Why is that? because the relationship between a degree in kelvin and degrees in celsius is addition...

Please give Ace some feedback